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**Two solutions** for the **triangle** This case is not solvable in all cases; a **solution** is guaranteed to be unique only if the side length adjacent to the angle is shorter than the other side length.

11M subscribers. There are three possible cases: ASA, AAS, **SSA**.

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👉 Learn how to.

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Learn how to work with the law of sines to decide whether there is 1 **triangle**, 2 **triangles** or no **triangle** possible when given **SSA** also known as the ambiguous.

10. Beneath each formula is shown a spherical **triangle** in which the four elements contained in the formula are highlighted. Y < 90° and all the choices depend on b sin A or z sin Y ≈ 6.

. In this case, the** Law of Sines** isn’t an option.

Given **two** adjacent side lengths and an angle opposite one of them (**SSA** o.

There are three possible cases: ASA, AAS, **SSA**.

If a ≥ b, then there is always exactly one **solution**. Mr.

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Use the Law of Cosines again to find the other angle.

To **solve** an SAS **triangle**.

In a right **triangle**, you use the trig ratios to **solve** it. . For example, let's take a **triangle** with the following parameters: a = 4 cm.

Apr 26, 2012 · Given **two** adjacent side lengths and an angle opposite one of them (SSA or ASS), then there are 3 possible cases: there can be 1 **solution**, 2 **solutions** and no **solution**. This depicts the **SSA** case for **triangles**, in which **two** sides and one of their opposite angles are given. **SSA triangles**, as was taught in the lesson, can have zero **solutions**, one **solution**, or **two solutions**. **SSA** **triangles**, as was taught in the lesson, can have zero **solutions**, one **solution**, or **two solutions**. If a b and α is obtuse we have no **solution** at all. .

Learn how to work with the law of sines to decide whether there is 1 **triangle**, 2 **triangles** or no **triangle** possible when given **SSA** also known as the ambiguous.

Use the Law of Cosines again to find the other angle. **solve** for the **2** possible values of the 3rd side b = c*cos (A) ± √ [ a **2** - c **2** sin **2** (A) ] [1] for each set of **solutions**, use The Law of Cosines to **solve** for each of the other **two**.

**Solve** ∆XYZ where Y = 50°, y = 8, and z = 9.

See Example \(\PageIndex{4}\).

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When given **two** sides and a non included angle (**SSA**) in a **triangle**, this is known as the ambiguous case for Law of Sines.

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